High school (9–12)
Science
Chemistry: Stoichiometry: Challenge
Free high school chemistry practice on stoichiometry. Convert between moles and mass, use mole ratios from balanced equations, and solve limiting reactant problems. Stretch thinking with multi-step problems, application questions, and deeper reasoning.
Hard Level Guide
Stretch thinking with multi-step problems, application questions, and deeper reasoning.
The Mole Concept
One mole equals 6.02 × 10²³ particles (Avogadro's number). Molar mass in g/mol converts between grams and moles. For water, 18 g is one mole of H₂O molecules.
Balanced Chemical Equations
Coefficients show mole ratios in a reaction. Balance by adjusting coefficients, never subscripts. A balanced equation obeys the law of conservation of mass: atoms are neither created nor destroyed.
Mole-to-Mole Calculations
Use coefficients as conversion factors. If 2H₂ + O₂ → 2H₂O, then 2 mol H₂ produces 2 mol H₂O. Set up dimensional analysis: given → moles → moles product → grams if needed.
Limiting Reactant and Percent Yield
The limiting reactant runs out first and caps product amount. Excess reactant remains. Percent yield = (actual yield / theoretical yield) × 100%. Real reactions rarely reach 100% due to side reactions and loss.
FAQ
- Do I need a calculator?
- Yes. Stoichiometry problems involve multiplication and division with molar masses.
- Is balancing equations covered?
- The pack assumes you can balance equations. Focus is on mole ratio calculations.